On Tue, Jul 11, 2000 at 11:34:59PM +0000, Herbert Xu wrote:
> > Except that in Perl the $ord would normally be interpreted as the variable
> > $ord, and thus the $ needs to be quoted (or some other quoting would be
> > required).
> 
> But in the scope of a regex, the first $ can not be interpreted as the prefix
> of a variable.  The second may be but only if you use s///e.

Umm..  Perl disagrees with you :)

isd70{showard}5: cat q.pl
#!/usr/bin/perl

$aa="bb";
while(<>) {
        s/$aa/xx/g;
        print;
}
isd70{showard}6: ./q.pl
$aa                     <- Enter this
$aa                     <- It didn't match
bb                      <- Enter this
xx                      <- And it did!
isd70{showard}7: 

It's matching on the contents of the variable, not "$aa".

  Scott.


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