> > I need to parse a date of the form DD/MM/YYYY > ^[0-3][0-9]\/[01][0-9]\/[0-9][0-9][0-9][0-9]$ Thanks john, This will discover if the date is not of the form DD/MM/YYYY right ? Or am i reading it wrong ? Jason -- SLUG - Sydney Linux User Group Mailing List - http://slug.org.au/ More Info: http://slug.org.au/lists/listinfo/slug
- [SLUG] Regex Question Jason Rennie
- Re: [SLUG] Regex Question John Ferlito
- Re: [SLUG] Regex Question Jason Rennie
- Re: [SLUG] Regex Question John Ferlito
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- RE: [SLUG] Regex Question David Zverina
- RE: [SLUG] Regex Question Jason Rennie
- [SLUG] Regex question Alexander Samad
- Re: [SLUG] Regex question Jamie Wilkinson
- Re: [SLUG] Regex question Alexander Samad
- Re: [SLUG] Regex question Jamie Wilkinson
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