* This one time, at band camp, Jobst Schmalenbach said:
> On Tue, Sep 18, 2001 at 04:43:06PM +1000, Mikolaj J. Habryn
>([EMAIL PROTECTED]) wrote:
> > On Tue, Sep 18, 2001 at 04:30:30PM +1000, Jobst Schmalenbach wrote:
> > > ".*@.*"
> > > I want to match only the last quoted string eg ".*@.*
> > > where the " is the last before the @
> >
> > "[^"]*@[^"]*"
>
> You win :-))
>
> Could you explain? I did some reading (I have Jeffrey Friedl's RegExp book)
> but dont understand how your regexp works.
>
It works - but its not precise. It is saying
Match " : "
Match anynumber of chars that are not " : [^"]*
Match @ : @
Match anynumber of chars that are not " : [^"]*
Match " : "
By any number - I also mean 0 - hence one of the problems...
,"[\w\d._]+@[\w\d.\-]+"$
is a more precise (though by no means complete) solution for your
current issue (tested with perl but the theory is sound)
Match a comma then double quote : ,"
Match any number (but at least 1) letter, word, . or _ : [\w\d._]+
Match @
: @
Match any number (but at least 1) letter, word, . or - : [\w\d.\-]+
Match " followed by end of line : "$
As you can see - you can adapt this one to allow more things (or
disallow them). Matching valid email addresses is not an easy task for
a single regex.
HTH
Greeno
--
Greeno <[EMAIL PROTECTED]>
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