OK.. I figure some things out and this is really messy I know but at least
it works for me...
print "Content-type: text/plain\n\n";
if ( "$in{eventdate}" !~ /^[0-9]+[\/]+[0-9]+[\/]+[0-9]+[0-9]+[0-9]+[0-9]$/
){
print "TBA";
exit(0);
}
else
{
$date=$in{eventdate};
$event=`date -d \"$date\" +\"%s\"`;
$nowdate=`date +"%s"`;
$daysleft=int (eval ((( $event - $nowdate ) / 86400 )));
print "$daysleft";
}
Thanks for all your help.. will try the full perl when I get around to it..
George Vieira
Systems Manager
Citadel Computer Systems P/L
-----Original Message-----
From: George Vieira
Sent: Tuesday, 18 December 2001 1:02 PM
To: Sydney Linux Users Group (E-mail)
Subject: RE: [SLUG] subracting dates from dates
Thanks to all that replied..
I found a way to do it in bash but now want to use perl to check the passed
in date for it's format ie... mm/dd/yyyy format.
I'd be happy with just 00-99 numbers..
At the moment I've done this (below) in shell commands in perl but wanted to
pass in $date is possible and checked too for errors.. I've taken a big
guess and tried it.. it seems to work (OMG) but would like suggestions...
# This part was original test and works but want $in{eventdate} to replace
$date
$date=02/23/2002";
$event=`date -d "\$date" +"%s"`;
$nowdate=`date +"%s"`;
$daysleft=`echo "$((($event - $nowdate) / 86400 ))"`;
if ( "$in{eventdate}" !~ /^[0-9]+[\/]+[0-9]+[\/]+[0000-9999]+$/ ){
print <<"EOT";
Content-type: text/plain
Invalid Date Format with $in{eventdate}
EOT
exit(0);
}
else
{ print "$in{eventdate} is just fine";
any help with this I appreciate it.
thanks,
George Vieira
Systems Manager
Citadel Computer Systems P/L
-----Original Message-----
From: Tony Green [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, 18 December 2001 12:00 PM
To: Sydney Linux Users Group (E-mail)
Subject: Re: [SLUG] subracting dates from dates
* This one time, at band camp, George Vieira said:
> Hi all,
>
> Is there a way to subtract the number of days remaining from a date so I
can
> report back "125 days remaining" etc.. under linux/perl?
>
> I want to subtract it from a date which will be a special event etc..
> Is there a date to interger conversion or something?
>
If your dates are in Epoch seconds, and fall in the range Fri Dec 13
20:45:52 1901 to Tue Jan 19 03:14:07 2038 (inclusive), simply subtract one
from the other and convert the seconds to days.
$seconds = $recent - $earlier;
If you have distinct DMYMHS values, or are worried about the range
limitations of Epoch seconds, use the Date::Calc module from CPAN. It can
calculate the difference between dates:
use Date::Calc qw(Delta_Days);
$days = Delta_Days( $year1, $month1, $day1, $year2, $month2, $day2);
It also calculates the difference between dates and times:
use Date::Calc qw(Delta_DHMS);
($days, $hours, $minutes, $seconds) =
Delta_DHMS( $year1, $month1, $day1, $hour1, $minute1, $seconds1, #
earlier
$year2, $month2, $day2, $hour2, $minute2, $seconds2); # later
Discussion
One problem with Epoch seconds is how to convert the large integers back to
forms that people can read. The following example shows one way of
converting an Epoch seconds value back to its component numbers of weeks,
days, hours, minutes, and seconds:
$bree = 361535725; # 16 Jun 1981, 4:35:25
$nat = 96201950; # 18 Jan 1973, 3:45:50
$difference = $bree - $nat;
print "There were $difference seconds between Nat and Bree\n";
There were 265333775 seconds between Nat and Bree
$seconds = $difference % 60;
$difference = ($difference - $seconds) / 60;
$minutes = $difference % 60;
$difference = ($difference - $minutes) / 60;
$hours = $difference % 24;
$difference = ($difference - $hours) / 24;
$days = $difference % 7;
$weeks = ($difference - $days) / 7;
print "($weeks weeks, $days days, $hours:$minutes:$seconds)\n";
(438 weeks, 4 days, 23:49:35)
Date::Calc's functions can ease these calculations. The Delta_Days function
returns the number of days between two dates. It takes the two dates as a
list: year, month, day. The dates are given chronologically - earliest
first.
use Date::Calc qw(Delta_Days);
@bree = (1981, 6, 16); # 16 Jun 1981
@nat = (1973, 1, 18); # 18 Jan 1973
$difference = Delta_Days(@nat, @bree);
print "There were $difference days between Nat and Bree\n";
There were 3071 days between Nat and Bree
The Delta_DHMS function returns a four-element list corresponding to the
number of days, hours, minutes, and seconds between the two dates you give
it.
use Date::Calc qw(Delta_DHMS);
@bree = (1981, 6, 16, 4, 35, 25); # 16 Jun 1981, 4:35:25
@nat = (1973, 1, 18, 3, 45, 50); # 18 Jan 1973, 3:45:50
@diff = Delta_DHMS(@nat, @bree);
print "Bree came $diff[0] days, $diff[1]:$diff[2]:$diff[3] after Nat\n";
Bree came 3071 days, 0:49:35 after Nat
See Also
The documentation for the CPAN module Date::Calc
--
Greeno <[EMAIL PROTECTED]>
GnuPG Key : 1024D/B5657C8B
Key fingerprint = 9ED8 59CC C161 B857 462E 51E6 7DFB 465B B565 7C8B
Imagine working in a secure environment and finding the string
_NSAKEY in the OS binaries without a good explanation
-Alan Cox 04/05/2001
--
SLUG - Sydney Linux User Group Mailing List - http://slug.org.au/
More Info: http://lists.slug.org.au/listinfo/slug
--
SLUG - Sydney Linux User Group Mailing List - http://slug.org.au/
More Info: http://lists.slug.org.au/listinfo/slug
--
SLUG - Sydney Linux User Group Mailing List - http://slug.org.au/
More Info: http://lists.slug.org.au/listinfo/slug
