On Wed, Feb 20, 2002 at 10:07:31PM +1100, getadog wrote:
> On Wed, Feb 20, 2002 at 07:06:53PM +1100, Grant Parnell wrote:
> > #!/bin/bash
[...]
> > LET COUNT=$COUNT+1
[...]
> Not sure what LET does, either, perhaps COUNT=$(( $COUNT + 1 ))
bash-2.03$ help let
let: let arg [arg ...]
Each ARG is an arithmetic expression to be evaluated. Evaluation
is done in long integers with no check for overflow, though division
by 0 is trapped and flagged as an error. The following list of
operators is grouped into levels of equal-precedence operators.
The levels are listed in order of decreasing precedence.
-, + unary minus, plus
!, ~ logical and bitwise negation
*, /, % multiplication, division, remainder
+, - addition, subtraction
<<, >> left and right bitwise shifts
<=, >=, <, > comparison
==, != equality, inequality
& bitwise AND
^ bitwise XOR
| bitwise OR
&& logical AND
|| logical OR
expr ? expr : expr
conditional expression
=, *=, /=, %=,
+=, -=, <<=, >>=,
&=, ^=, |= assignment
Shell variables are allowed as operands. The name of the variable
is replaced by its value (coerced to a long integer) within
an expression. The variable need not have its integer attribute
turned on to be used in an expression.
Operators are evaluated in order of precedence. Sub-expressions in
parentheses are evaluated first and may override the precedence
rules above.
If the last ARG evaluates to 0, let returns 1; 0 is returned
otherwise.
Scott
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