>>>>> "henry" == henry <[EMAIL PROTECTED]> writes:
henry> Dear List : How to replace 0xabcd,0xefgh to 0xab,0xcd,0xef,0xgh henry> ? (Note: a,b,c... is variable digital resp.) How can I replace henry> [0-9][0-9], with 0x[0-9][0-9] ? I think you want something like: sed -e 's/\(0x[0-9a-fA-F][0-9a-fA-F]\)\([0-9a-fA-F][0-9a-fA-F]\)/\1,0x\2/g' The parentheses \(\) mark out portions of the matched expression; \1 is whatever was matched by the first such, \2 by the second and so on. The trailing `g' says to repeat the substitution on all matches found, not just the first in the line. -- Dr Peter Chubb [EMAIL PROTECTED] You are lost in a maze of BitKeeper repositories, all almost the same. -- SLUG - Sydney Linux User's Group - http://slug.org.au/ More Info: http://lists.slug.org.au/listinfo/slug
