Re: [SLUG] bash programming question

[David Kempe]

John Clarke wrote:

On Mon, Feb 16, 2004 at 10:13:28 +1100, David Kempe wrote:
#if (( "ERRORNUM" >= 1 ))
if [ "$ERRORNUM" != 0 ]


!= is a string operator.  You want to do a numeric comparison:

Yes I realise I want to do a numeric comparision - only problem is it 
doesn't work:

ERRORNUM=`grepstuff $LOGTMP |totalerrors`
echo $STATUS
echo $ERRORNUM
#if (( ERRORNUM -ge 1 ))
if [ "$ERRORNUM" -ge 1 ]
        #then let STATUS="$STATUS but with errors"
        then STATUS="$STATUS but with errors"
        else echo status screwed
fi
produces:

54
: integer expression expected
status screwed
and if I try is with round brackets as was suggested:
ERRORNUM=`grepstuff $LOGTMP |totalerrors`
echo $STATUS
echo $ERRORNUM
if (( ERRORNUM -ge 1 ))
#if [ "$ERRORNUM" -ge 1 ]
        #then let STATUS="$STATUS but with errors"
        then STATUS="$STATUS but with errors"
        else echo status screwed
fi
gives this:

54
")syntax error: operand expected (error token is "
status screwed
single round brackets:
54
./parse.sh: ERRORNUM: command not found
status screwed
I think double round brackets is what I want ((...)) from the Adv Bash 
HOWTO, but the syntax error throws me. It suggests that I need an 
operand but I clearly have one... In the last example I tried >= as well....

as for the quoting (thanks jeff) I think strings need quoting, integers 
don't. [] seems to be for strings, ((..)) and (...) for numbers - am I 
getting anywhere? hrmm...

thanks for you help so far..

dave

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