I've been fiddling around with some MD5 code in coreutils,
and discovered this weirdness with gcc:
#include <stdio.h>
void showsize(unsigned char arg[16])
{
unsigned char stack[16];
fprintf(stderr,"[sizeof(arg) = %d]\n",sizeof(arg));
fprintf(stderr,"[sizeof(stack) = %d]\n",sizeof(stack));
}
int main()
{
unsigned char m[16];
showsize(m);
return 0;
}
The output:
[sizeof(arg) = 4]
[sizeof(stack) = 16]
Can anyone explain why the size of arg differs from the array
on the stack?
Is C treating arg as a char* so that sizeof(arg) is sizeof(char*)?
cheers
rickw
--
_________________________________
Rick Welykochy || Praxis Services
When choosing between two evils, I always like to take the one I haven't tried
before.
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