[EMAIL PROTECTED] wrote:
I find this interesting.
<snipped>
char* somefunction()
{
char string2[] = "some words";
return string2;
}
--------------------------------------
doesn't
Hi Yiz,
A couple of people have explained why the above does
not work.
My attention will focus on How to make it work.
As suggested, the main requirement is to have a pointer that you can use
to manipulate
the string around. So, I modified the function to get,
char*
somefunction()
{
char * string1; /* I define a char pointer since
your array is char string */
char string2[] = "some words";
string1 = malloc(11); /* In the context of this program, it
is sufficient to set aside 11 bytes */
strcpy(string1,string2); /* I duplicate string2 into string1 */
return string1; /* I return address of string1 to
become the value of somefunction() */
/* which is passed on to
main() and then printed by main() */
}
int main(void) /* I added main function to complete a test
program */
{
printf("\nThe string is: %s\n", somefunction()); /*
somefunction() initialised and printed */
return 0;
}
You appear to be a keen user of C.
One suggestion, learn to use GDB ( http://www.gnu.org/software/gdb/ ) if
you have'nt yet.
This package will help you understand further why the original
'somefunction()' did not work.
Hope this helps.
O Plameras
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