Put this into your .bashrc file:
function fstr()
{
OPTIND=1
local case=" "
local usage="fstr: find string in files.\nUsage: fstr [-i] \"pattern\"
[\"filename pattern\"] "
while getopts :it opt
do
case "$opt" in
i) case="-i " ;;
*) echo "$usage"; return;;
esac
done
shift $(( $OPTIND - 1 ))
if [ "$#" -lt 1 ]; then
echo "$usage"
return;
fi
local SMSO=$(tput smso)
local RMSO=$(tput rmso)
find . -type f -name "${2:-*}" -print0 | xargs -0 grep -sn ${case} "$1"
2>&- | sed "s/$1/${SMSO}\0${RMSO}/gI" | more
}
... comes with the lot, even highlighting.
;-)
Jobst
On Fri, Nov 14, 2008 at 07:14:22PM +1100, [EMAIL PROTECTED] ([EMAIL PROTECTED])
wrote:
> Is there a command that finds a file containing a certain word?
>
> find and apropos don't. They work on filenames only.
>
> Using Hardy H.
>
> Any suggestions gratefully etc.
>
> Bill Bennett
> --
> SLUG - Sydney Linux User's Group Mailing List - http://slug.org.au/
> Subscription info and FAQs: http://slug.org.au/faq/mailinglists.html
--
When you lose, don't lose the lesson.
| |0| | Jobst Schmalenbach, [EMAIL PROTECTED], General Manager
| | |0| Barrett Consulting Group P/L & The Meditation Room P/L
|0|0|0| +61 3 9532 7677, POBox 277, Caulfield South, 3162, Australia
--
SLUG - Sydney Linux User's Group Mailing List - http://slug.org.au/
Subscription info and FAQs: http://slug.org.au/faq/mailinglists.html
