On Fri, Jun 20, 2008 at 7:32 AM, Yanto Young <[EMAIL PROTECTED]> wrote:
> Hi guys,
>
> I would like to know if there's a quick and dirty method (using
> bash/sed/awk) to perform the following:
I'm not that good with bash/sed/awk but yeah, it's possible, can't
outline the exact details, but roughly:
1) Set up a variable to hold the results
2) Use regular expression /(t=\d+\s)(\d+)/, the RegExp will make the
second number accessible easily, add that to the counter
3) Print the results.
Here is a Perl script that does that
#/usr/bin/perl
var result = 0;
open(FILE, '...') || die 'Can't open file';
while ( <FILE> ) {
chomp;
if ($_ =~ /(t=\d+\s)(\d+)/) {
$result += $2;
print $1, $result;
} else {
die 'File format is wrong.';
}
}
Hope that helps (didn't test that though, but it should work). The
script output the result to stdout, but you can easily redirect that
using > or >> in command line. e.g.
$ ./transform input > output
>
> Original file:
> *******************
> t=0 1
> t=1 1
> t=2 -1
> t=3 1
> t=4 1
> t=5 -1
> *******************
>
> Desired result:
> *******************
> t=0 1
> t=1 2
> t=2 1
> t=3 2
> t=4 3
> t=5 2
> *******************
>
> that is, I would like to perform cumulative addition on the second column.
>
>
> Thanks.
>
> Best regards,
> Yanto
--
Chris
[EMAIL PROTECTED]
[EMAIL PROTECTED]
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