I try do this, but seems still have timeout exception. I think this a same way to delete message, because in the source code Service.java line 967, it use the same way to do this.
On 1月4日, 下午5时25分, Andy <[email protected]> wrote: > Do you mean like this: > Service.getInstance().getGateway(inboundMessage.getGatewayId()).deleteMessa > ge(inboundMessage)? > > On 1月4日, 下午4时42分, Nizam Mohideen <[email protected]> wrote: > > > > > > > > > Have you tried the Gateway.deleteMessage method? > > > On Wed, Jan 4, 2012 at 1:33 PM, Andy <[email protected]> wrote: > > > Hi All, > > > > follow is my code section: > > > > for (InboundMessage inboundMessage : msgList) { > > > > System.out.println(inboundMessage.getMemIndex() + " " + > > > inboundMessage.getMemLocation() + " " + > > > inboundMessage.getGatewayId()); > > > > System.out.println(Service.getInstance().deleteMessage(inboundMessage)); > > > } > > > > In this loop, first will print the memIndex and memLocation and > > > gatewayId like this: > > > > 1, "SM", "modem.com3" > > > > then there will throw the timeout exception in > > > Service.getInstance().deleteMessage(inboundMessage) method. > > > > I am sure the service is started and the gateway is normal because it > > > can send message simultaneously. > > > > Please help me, thanks. > > > > -- > > > You received this message because you are subscribed to the Google Groups > > > "SMSLib Discussion Group" group. > > > To post to this group, send email to [email protected]. > > > To unsubscribe from this group, send email to > > > [email protected]. > > > For more options, visit this group at > > >http://groups.google.com/group/smslib?hl=en. -- You received this message because you are subscribed to the Google Groups "SMSLib Discussion Group" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/smslib?hl=en.
