The ptoblem is when the thread marked as interrupted, it does not release lock 
on wait(), but throw an InterruptedException immediately.


Dmitrii Krendelev
________________________________________
От: SNMP4J [[email protected]] от имени Dmitrii Krendelev 
[[email protected]]
Отправлено: 18 декабря 2014 г. 23:22
Кому: Frank Fock; [email protected]
Тема: [SNMP4J] HA: [BugReport][SNMP4J-2.2.3] Concurrency bug    in      
org.snmp4j.util.ThreadPool.

Hi, Frank,

Thanks for answer!

> ... if no TaskManager is there to handle the task.

To become available, TaskManager need to execute section below

synchronized (ThreadPool.this)
{
        this.task = null;
        ThreadPool.this.notify();
}

But ThreadPool.this is blocked by  synchronized 'execute' method, so 
TaskManager-threads will never be available. And when we reach wait() method 
again, InterruptedException will be thrown again, so here is a cycle! We do not 
unlock the ThreadPool.this! 
(http://docs.oracle.com/javase/specs/jls/se7/html/jls-17.html ) This process 
will never stop since once we got an InterruptedException.


Dmitrii Krendelev

________________________________________
От: SNMP4J [[email protected]] от имени Frank Fock [[email protected]]
Отправлено: 18 декабря 2014 г. 22:43
Кому: [email protected]
Тема: Re: [SNMP4J] [BugReport][SNMP4J-2.2.3] Concurrency bug in 
org.snmp4j.util.ThreadPool.

Hi Dimitrii,

When an InterruptedException is thrown in wait() it will be catched and
a new interrupt()
will be triggered. If not handled, the TaskManager continues in the loop
but then finally
calls wait() again, if no TaskManager is there to handle the task.

I do not see any problem with the original code (which is different from
what you quoted
below).

Best regards,
Frank

Am 18.12.2014 11:49, schrieb Dmitrii Krendelev:
> Hi,
>
> We have found quite a critical bug in 
> org.snmp4j.util.ThreadPool.execute(WorkerTask task) method. It has an execute 
> method below
>
>      public synchronized void execute(WorkerTask task)
>      {
>          while (true)
>          {
>              // here we check if some TaskManager-thread is free to execute 
> the task.
>              try
>              {
>                  wait(); // wait until some TaskManager-thread notify that it 
> finished a previous task
>              }
>              catch (InterruptedException ex)
>              {
>                  Thread.currentThread().interrupt();
>              }
>          }
>       }
>
> If  InterruptedException is thrown, so our thread goes into cycle and keep 
> the lock on the ThreadPool object, so TaskManager-threads cannot notify that 
> they became free as soon as they blocked on the ThreadPool. So if the 
> interrupt was called when NO TaskManager-threads were free to execute the 
> task, so the process just hangs.
>
> There is a simple way to fix it. We need just to break the cycle if the 
> process was interrupted and not to execute task like below.
>
>      public synchronized void execute(WorkerTask task)
>      {
>         try
>          {
>
>             while (true)
>             {
>                 // here we check if some TaskManager-thread is free to 
> execute the task
>                 wait();// wait until some TaskManager-thread notify that it 
> finished a previous task
>             }
>          catch (InterruptedException ex)
>          {
>             Thread.currentThread().interrupt();
>          }
>
>      }
>
> Thanks,
>
> Dmitrii Krendelev
>
>
>
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