You want to use the getBody method of Envelope. In turn, the
getBodyEntries method of Body will let you access the immediately
children of the <s:Body> element. Normally, this would be the method
call (below you have <name>, which I would guess to be a SOAP struct).
Scott Nichol
----- Original Message -----
From: <[EMAIL PROTECTED]>
To: "SOAP-Dev" <[EMAIL PROTECTED]>
Sent: Thursday, October 10, 2002 5:58 AM
Subject: Parsing SOAP message request in Java
> Hi All,
>
> I want to know how can i access a request that has been sent thru the
> message.sent() method ..
>
> for example..
> i send my xml document through this soap method
>
> msg.send (new URL ("http://localserver/soap/messagerouter";),
> "urn:testservice", msgEnv);
>
> where msgEnv parsed is a soap xml. which contains the following xml
file
> <?xml version="1.0" encoding="UTF-8" ?>
> <s:Envelope xmlns:s="http://schemas.xmlsoap.org/soap/envelope/";>
> <s:Body>
> <name>
> <first>
> XXX
> </first >
> <last>
> YYY
> </last>
> </name>
> </s:Body>
> </s:Envelope>
>
> 1) now i need to parse the soap/xml document in the mentod called
> doRegister() deployed in urn:testservice.
> 2)
> here is am sample of the method doRegister
>
>
> public void doRegistration(Envelope env, SOAPContext req, SOAPContext
res)
> throws IOException, MessagingException
> {
>
> try{
>
> String firstName = null;
> String lastName = null;
> String output =null;
>
> Vector lovcEntries = env.getEnvelopeEntries(); //trying to
get
> the xml file contents
>
> }
>
>
> catch(Exception ex){
>
> System.out.println("Exception in the RegisterService ::
> doRegistration()");
>
> }
> }
>
> i want to get the first and last name tag's from the SOAP/xml. how do
i get
> it. but by using the above env.getEnvelopeEntries() i am not able to
get
> entries. Can anyone suggest me how to parse the Sent xnl fine.
>
> can anyone help me pls....
>
> Thanks,
> Kavitha
>
>
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