Hi,
You can use toop TcpTunnel provided with Apache soap :
java org.apache.soap.util.net.TcpTunnelGui 8070 localhost 80
SAINT-MARTIN Cecile
[EMAIL PROTECTED]
> -----Message d'origine-----
> De : Marc Chachereau [mailto:[EMAIL PROTECTED]]
> Envoye : jeudi 14 juin 2001 10:52
> A : [EMAIL PROTECTED]
> Objet : How to get the HTTP SOAP request
>
>
> I've just installe Apache SOAP and I've written a "HelloWorld" test.
> I success to make it working. My client sends a SOAP request with
> the API and
> thanks to the Call object and the following methods :
> setTargetObjectURI()
> call.setMethodName()
> call.setEncodingStyleURI()
> call.setParams()
> But I would like to see this request and so the xml soap message
> generated.
> How to do that ?
> Thank you.
> Marc.
>
>
> ---------------------------------------------------------------------
> To unsubscribe, e-mail: [EMAIL PROTECTED]
> For additional commands, email: [EMAIL PROTECTED]
>
---------------------------------------------------------------------
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, email: [EMAIL PROTECTED]
