Hey ,

I am new to soap I am invoking one service on xmlmethods.net

My Client code is --

import java.io.*;
import java.net.*;
import java.util.*;
import org.apache.soap.util.xml.*;
import org.apache.soap.*;
import org.apache.soap.rpc.*;

public class TempClient{

    public static float getTemp (URL url, String zipcode) throws
Exception {

        Call call = new Call ();

        // Service uses standard SOAP encoding
        String encodingStyleURI = Constants.NS_URI_SOAP_ENC;
        call.setEncodingStyleURI(encodingStyleURI);

        // Set service locator parameters
        call.setTargetObjectURI ("urn:xmethods-Temperature");
        call.setMethodName ("getTemp");

        // Create input parameter vector
        Vector params = new Vector ();
        params.addElement (new Parameter("zipcode", String.class,
zipcode,null));
        call.setParams (params);

        // Invoke the service ....
        Response resp = call.invoke (url,"");

       // ... and evaluate the response
        if (resp.generatedFault ()) {
            throw new Exception();
        } else {
          // Call was successful. Extract response parameter and return

            Parameter result = resp.getReturnValue ();
            Float rate=(Float) result.getValue();
            return rate.floatValue();
        }
    }

// Driver to illustrate service invocation
    public static void main(String[] args)
    {
    try
        {
            URL url=new
URL("http://services.xmethods.com:80/soap/servlet/rpcrouter";);
            String zipcode= "94041";
            float temp = getTemp(url,zipcode);
            System.out.println(temp);
        }
    catch (Exception e) {e.printStackTrace();}
    }
}


I get following error.

[SOAPException: faultCode=SOAP-ENV:Client; msg=Error opening socket:
Connection
timed out: connect; targetException=java.lang.IllegalArgumentException:
Error op
ening socket: Connection timed out: connect]
        at
org.apache.soap.transport.http.SOAPHTTPConnection.send(SOAPHTTPConnec
tion.java:324)
        at org.apache.soap.rpc.Call.invoke(Call.java:205)
        at TempClient.getTemp(TempClient.java:28)
        at TempClient.main(TempClient.java:49)

Is any one has any guess, I will really appreciate any help on the same.

Regards,

Vijay

"W. Scott Grant" wrote:

> A signature match usually means that the parameters you send to
> the method do not exactly match the expected order listed.  In other
> words if you have the following method
>
> run(String a, String b, int c) and you try to call it using
>
> run(int c, String a, String b) you will get a signature error.
>
> > -----Original Message-----
> > From: C. Schlegelmilch [mailto:[EMAIL PROTECTED]]
> > Sent: Friday, April 12, 2002 3:17 PM
> > To: [EMAIL PROTECTED]
> > Subject: No Signature Match
> >
> >
> > Hello,
> >
> > I've searched the archives and the web and have yet to
> > see a solid answer that works for me:
> >
> > With a SOAP Messaging service implemented using Apache
> > SOAP.  My service calls a method called run().  It
> > contains the following signature:
> >
> > public void run (org.apache.soap.Envelope
> > env,org.apache.soap.rpc.SOAPContext
> > reqCtx,org.apache.soap.rpc.SOAPContext resCtx)
> >
> > My service constantly returns the following error:
> > Exception while handling service request:
> > com.cssde.server.RecordRouter.run(org.apache.soap.Envelope,org.apa
> > che.soap.rpc.SOAPContext,org.apache.soap.rpc.SOAPContext)
> > -- no signature match
> >
> > Have no clue why.
> >
> > Running Tomcat 4.0.1 on Win2000 with JDK 1.3.1.
> >
> > Any ideas?
> >
> > Thanks,
> >
> > Craig Schlegelmilch
> >
> > __________________________________________________
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> >
> >

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