Please who can help me trough this problem:
I still get null in the below specs. From the deployment description (the javaclass) I get to alright, thanks to scott.  When I display the fields in : public void purchaseOrder (Envelope env, SOAPContext reqCtx,
SOAPContext resCtx)
I get the MyHeader tag and MyBody tag, but with null, while there should be a lot more elements in there.
Through messaging I only need the whole string (whole soap message). With what function in my class can I get it.
 
I am learning every day now... but there are still some things (the header/body example) which I cannot figure out. I read a lot of info, but 2 and 2 is still not 4 at this moment.
 
Please Help!!!!!
 
Henk.
-----Original Message-----
From: Henk Schipper [mailto:[EMAIL PROTECTED]
Sent: woensdag 11 juni 2003 23:38
To: [EMAIL PROTECTED]
Subject: RE: Serializer/deserializer problem.....

Thanks for your reply
 
Unfortunately, I create a message from a microsoft client. Interop problem probably. I remeber reading about putting the namespace qualifiers in front of every element belonging to it. This client cannot do that.
In the java program 'transportMessage.java' I can print the whole soap message to the serverlog. But how can i forward (or read it) into the class using for a respons?
This is my big question. I hope you can assist me in this part.
 
Thanks for your help!!!! It is very appriciated!!!
 
Henk.
-----Original Message-----
From: Vishal Shah [mailto:[EMAIL PROTECTED]
Sent: woensdag 11 juni 2003 22:08
To: [EMAIL PROTECTED]
Subject: RE: Serializer/deserializer problem.....

Henk,
 
You can try this...

public void purchaseOrder (Envelope requestEnvelope, SOAPContext reqCtx,
SOAPContext resCtx) {

 try {

Body b = requestEnvelope.getBody();
Vector entries = b.getBodyEntries();
//interrogate this vector that contains elements

for(int i=0; i<entries.size(); ++i) {

Element e = (Element) entries.elementAt(i);

// get node name

nodeName = e.getNodeName();

//continue processing your elements...

}

 

}catch( Exception e ){

}

 

}

 



Henk Schipper <[EMAIL PROTECTED]> wrote:
Hi Scott,

Thanks for the first step. I got some response. Only the header and body
info, not the fields themselves. (the elements). I am sorry for being such a
newby... but how do i get the elements as well? I read about
marshalling..... how?
I hope you can help me?

Thanks.

Henk.

-----Original Message-----
From: Scott Nichol [mailto:[EMAIL PROTECTED]
Sent: woensdag 11 juni 2003 15:55
To: [EMAIL PROTECTED]
Subject: RE: Serializer/deserializer problem.....


With messaging, each method in your service must have a parameter
list like

public void purchaseOrder (Envelope env, SOAPContext reqCtx,
SOAPContext resCtx)

i.e. and Envelope and two SOAPContext. You then extract information
from the envelope and input context, then manipulate the output
context to send the result. See the messaging s! ample for simple
examples.

On 11 Jun 2003 at 11:17, Henk Schipper wrote:

> Scott,
>
> I would like to try the messaging, but whenever i try, i get
>
:'(org.apache.soap.Envelope,org.apache.soap.rpc.SOAPContext,org.apache.soap.
> rpc.SOAPContext) -- no signature match'
>
> And ... it finds the class ....it includes the method (here a snippit of
> the source:
>
> public String MyMethod(String fielda) throws IllegalArgumentException
> {
> System.out.println("MyMethod");
> // System.out.println(buf);
> String buf = "Output";
> return buf;
> }
>
> As you can see, only something to see if it works....
> What am i doing wrong? Please Help.
>
> Regards,
>
> Henk.
>
> -----Original Message-----
> From: Scott Nichol [mailto:[EMAIL PROTECTED]
> Sent: dinsdag 10 juni 2003 17:09
> To: [EMAIL PROTECTED]
> Subject: Re: Serializer/deserializer problem.....
>
>
> One way to access the XML that is the SOAP envelope is to use the
> messaging API.
>
> If you want to keep using the RPC API, there are a couple of ways to
> get at the XML. One is to create and install an envelope editor
> (http://ws.apache.org/soap/docs/guide/transhooks.html). This allows
> you to read the envelope and write a changed version. If you want to
> do checks and fail the call, you could throw a run-time exception.
>
> Alternatively, you can get access to SOAPContext in your service
> methods (http://ws.apache.org/soap/docs/guide/migration.html). You
> can use methods like getRootPart or getEnvelope to get the envelope.
>
> On 10 Jun 2003 at 14:50, Henk Schipper wrote:
>
> > Hi All,
> >
> > This subject is already in many different ways been discus! sed, but I
> cannot
> > find mine..... I hope you can help me.
> >
> > I am running Apache tomcat 4.1.24, xerces java2, soap 2.3.1
> > bsf/ant/mail/jaxp
> > Server is running well... other services are running well, but when i am
> > trying getting the example below to run, every time, i have the same
> > problem:
> >
> > Deserialiser:
> > package org.apache.soap.encoding.soapenc;
> >
> > import java.io.*;
> > import org.w3c.dom.*;
> > import org.apache.soap.util.xml.*;
> > import org.apache.soap.*;
> > import org.apache.soap.util.*;
> > import org.apache.soap.rpc.*;
> >
> > public class MyDeserializer implements Deserializer
> > {
> > public Bean unmarshall(String inScopeEncStyle, QName elementType,
> > Node src, XMLJavaMappingRegistry xjmr,
> > SOAPContext ctx) throws
IllegalArgumentException
> > {
> > System.out.println("DEBUG deserializer \n");
> > Element root = (Element)src;
> > String value = DOMUtils.getChildCharacterData(root);
> > return new Bean(String.class, value);
> > }
> > }
> >
> >
> > I attached the previous mail to this one for more information.
> >
> > Is there otherwise a way to pass the complete xml to a class with what i
> can
> > work with? Here I mean, pass directly the xml to the Provider Class with
> no
> > editing, so i can do my checks? I know.... this should not be the way,
but
> I
> > am desperate at the moment... and also ran out of time..
> >
> > ANY HELP IS APPRECEATED!!!!
> >
> > Thanks
> >
> > Henk.
> >
>
>
> Scott Nichol
>
> Do not reply directly to ! this e-mail address,
> as it is filtered to only receive e-mail from
> specific mailing lists.
>
>
>
>


Scott Nichol

Do not reply directly to this e-mail address,
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