Okay, didn't read your example carefully the first time. I stand corrected.
Lincoln Ross wrote:
>
> see below:
>
> Brett Jaffee wrote:
> >
> > Lincoln Ross wrote:
> > >
> > > No. It doesn't work that way. Consider the case of an Apogee (numbers
> > > per design spec) where you are downwind, trying to fight a 4M/s wind to
> > > get back to the field, and your best L/D is at 4M/s airspeed. Wouldn't
> > > it pay to speed up, even if you came down faster? Unless you like
> > > bushwacking of course.
> >
> > No, I don't understand this. L/D is a measure of how far you can go through an
>airmass with the amount of >altitude you have. I don't see how the the wind factors
>into it. The bottom line is that I want to convert >my altitude into a horizontal
>distance through the air in the most efficient way possible, so I can go as far
>>horizontally through the air as possible. I don't see how the wind factors in.
>
> That's fine if you're flying from a balloon. It definitely maximizes
> distance thru the air, but that air is moving. If you have to make the
> field you have to go over the ground, as well as thru the air. Read it
> again. Just to hold still you have to make 4M/s. That amount is
> subtracted from any speed you are making over the ground.
>
> How fast would you row to go upstream in a 2 knot current?
> > >
> > > It also turns out that if you go faster than your best L/D you will get
> > > out of sink faster.
> >
> > Okay, but I'm just talking about dead air, or a constant horizontal wind (however
>realistic that case may be), as that was the original example. Lift or sink will
>obvisouly change the situation.
>
> Yup. Sorry about that.
> >
> > Brett
>
> --
> Lincoln Ross
--
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