Grant,
Thanks for your input.

>Lets assume that the signals are quite
>strong, and are at 27 and 28MHz, i.e. 1MHz spacing.
>The closest IMD products will be at 26 and 29MHz, and will be at equal
>amplitude. These are the third order IMD products, because they are
>procuced by the 2nd harmonic of each of the two input signals mixing
>with the fundamental of the other. We will ignore the other IMD
>products for this discussion.
>


Ok, let me do some number crunching with the numerical values you gave.

Second harmonic of 27 and 28MHz are 54MHz and 56MHz.
So a 54MHz signal is added two a 28 MHz signal, with some non
linearity function after that. So I get the sum and products: 26 and
70MHz. Doing the same with 56 and 27, I get 29 and 83MHZ. With
filtering, I will only keep the contents near the IF bannd: 26, 27, 28
and 28Mhz.
Ok, I it matches so far.





>Now, it gets more tricky - if the level of BOTH of the input signals
>is increased by 1dB, then the levels of the 3rd order IMD products
>will increase by 3DB.
I am still struggling here. I would assume that a model of

y(t)= a x(t)+ b x(t)^2 + c z(t) + d x(t) z(t) +e z(t)^2
x(t)=input signals = x1(t) + x2(t)
z(t)=local oscillator

I am trying to map this idea to the explanation you provided. I just
don't see how come in the below graph
http://en.wikipedia.org/wiki/Image:Interceptpoint.png

that the two lines don't start at the origin. The graph seems to give
me the below idea:

y(t)= a x(t)+ b (x(t)- f)^2 + c z(t) + d x(t) z(t) +e z(t)^2
which means that the IMD power is subtracted by a constant, next
scales up (slope b).
Physically, how do you get on the mixer a sudden little piece of power
cut off from the IMD total power?
Frank

> I hope that helps.
> 
> regards
> 
> Grant G8UBN
>


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