In a message dated 3/31/2006 12:11:32 P.M. Eastern Standard Time,
[EMAIL PROTECTED] writes:
Good Afternoon:
I need to write a script/execute a command and don't have a lot
of time to research. The script will take in the output from the ls -al
command and evaluate only the first 10 characters (the file type and
permissions). I want to copy out all the lines that have -********T or
-********t in the file permissions indicators. What is the best to do
this?
nawk/awk is good enough, in my view.
ls -al | awk '{if ((substr
($1,length($1),1)=="T")||(substr($1,(length($1),1)=="t")){print $0}}'
There are shorter ways to do this, but I don't have a Solaris machine in
front of me and can't test them.
As always, untested code has to be buggy. Contact me if it doesn't work.
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