But as far as I understand the total number of constraints is limited (there is a default value), so I cannot know the total if I don't set the facet.limit to a really big number and then the request takes a long time. I was wondering if there was a way to get the total number (e.g. 100.000 constraints) to show it to the user, and then paginate using facet.offset and facet.limit until I reach that total. Does this make sense?
Thanks! Bruno 2009/2/3 Markus Jelsma - Buyways B.V. <mar...@buyways.nl> > Hello, > > > Searching for ?q=*:* with facetting turned on gives me the total number > of available constraints, if that is what you mean. > > > Cheers, > > > > On Tue, 2009-02-03 at 16:03 +0000, Bruno Aranda wrote: > > > Hi, > > > > I would like to know if is there a way to get the total number of > different > > facets returned by a faceted search? I see already that I can paginate > > through the facets with the facet.offset and facet.limit, but there is a > way > > to know how many facets are found in total? > > > > For instance, > > > > Name Surname > > > > Peter Smith > > John Smith > > Anne Baker > > Mary York > > ... 1 million records more with 100.000 distinct surnames > > > > For instance, now I search for people with names starting with A, and I > > retrieve 5000 results. I would like to know the distinct number of > surnames > > (facets) for the result set if possible, so I could show in my app > something > > like this: > > > > 5000 people found with 1440 distinct surnames. > > > > Any ideas? Is this possible to implement? Any pointers would be greatly > > appreciated, > > > > Thanks! > > > > Bruno >
