you can also try URL urlo = new URL(url);// ensure that the url has wt=javabin in that NamedList<Object> namedList = new JavaBinCodec().unmarshal(urlo.openConnection().getInputStream()); QueryResponse response = new QueryResponse(namedList, null);
On Mon, Feb 8, 2010 at 11:49 PM, Jason Rutherglen <jason.rutherg...@gmail.com> wrote: > Here's what I did to resolve this: > > XMLResponseParser parser = new XMLResponseParser(); > URL urlo = new URL(url); > InputStreamReader isr = new > InputStreamReader(urlo.openConnection().getInputStream()); > NamedList<Object> namedList = parser.processResponse(isr); > QueryResponse response = new QueryResponse(namedList, null); > > On Mon, Feb 8, 2010 at 10:03 AM, Jason Rutherglen > <jason.rutherg...@gmail.com> wrote: >> So here's what happens if I pass in a URL with parameters, SolrJ chokes: >> >> Exception in thread "main" java.lang.RuntimeException: Invalid base >> url for solrj. The base URL must not contain parameters: >> http://locahost:8080/solr/main/select?q=video&qt=dismax >> at >> org.apache.solr.client.solrj.impl.CommonsHttpSolrServer.<init>(CommonsHttpSolrServer.java:205) >> at >> org.apache.solr.client.solrj.impl.CommonsHttpSolrServer.<init>(CommonsHttpSolrServer.java:180) >> at >> org.apache.solr.client.solrj.impl.CommonsHttpSolrServer.<init>(CommonsHttpSolrServer.java:152) >> at org.apache.solr.util.QueryTime.main(QueryTime.java:20) >> >> >> On Mon, Feb 8, 2010 at 9:32 AM, Jason Rutherglen >> <jason.rutherg...@gmail.com> wrote: >>> Sorry for the poorly worded title... For SOLR-1761 I want to pass in a >>> URL and parse the query response... However it's non-obvious to me how >>> to do this using the SolrJ API, hence asking the experts here. :) >>> >> > -- ----------------------------------------------------- Noble Paul | Systems Architect| AOL | http://aol.com
