On 14 February 2012 23:35, Mark <static.void....@gmail.com> wrote: > Thanks I'll have a look at this. I should have mentioned that the actual > values on the graph aren't important rather I was showing an example of how > the function should behave. [...]
>> either y = (100/(e^((x -50)/75)^2)) + 50 [...] In general, the exponential will be better behave than the sinusoid. You can change the exact values by tweaking the coeffiocients in the equation. Regards, Gora
