An actual Julian date is based on # of days since some time 3+ thousand 
years BC.

The dates CF is using are days since 12/30/1899.

To convert a date from a date format to a "CF Julian Date" (ie. the number 
of days since 12/30/1899) add 0 to the date so:
#dateFormat(now())# will show
Oct-04 2002

<cfset CFNow = now()+0>
<cfoutput>#cfnow#</cfoutput>
37533.4112269

At 02:31 PM 10/4/2002 +0100, you wrote:
>sorry Jeff, run that by me again?  Its Friday and I have a bit of a head
>block here....
>
>-----Original Message-----
>From: jeff tapper [mailto:[EMAIL PROTECTED]]
>Sent: 04 October 2002 14:23
>To: Spectra-Talk
>Subject: RE: Date / 37476.573935200?
>
>
>Well, if 0 is 12/30/1899, its not a real julian date, which should have 0
>as several thousand years earlier.  anyhow, if you want to make a CFJulian
>date of the current date/Time, try
>
><cfset CFJulianNow = now() + 0>
>
>At 02:09 PM 10/4/2002 +0100, you wrote:
> >thing is, how is creating the Julian date?
> >
> >-----Original Message-----
> >From: jeff tapper [mailto:[EMAIL PROTECTED]]
> >Sent: 04 October 2002 14:07
> >To: Spectra-Talk
> >Subject: Re: Date / 37476.573935200?
> >
> >
> >I was just playing with this the other day.  #DateFormat(0)# evaluates to
> >12/30/1899
> >
> >At 01:48 PM 10/4/2002 +0100, you wrote:
> > >Does anyone remember what this date number actually represents?  When you
> > >place it into a DateFormat() expression, it comes out as a proper date.
> > >
> > >I cant remember for the life of me what it means, I am sure its the time
>in
> > >seconds, minutes and hours since a certain data but I cant say for sure.
> > >
> > >thanks
> > >
> > >Neil
> > >
> >
> >
>
>
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