--- In [email protected], "Per Kristen Fredlund" 
<[EMAIL PROTECTED]> wrote:
>
> Hi!
> 
> That 'Arc de Triomphe' is so well known that i didn't bother to post 
> it yet. Even Stefan knows that one ;-)

That's right, even I knew that ;-)

Now here's a new task:

F' R' S' D' F' M F D S R F
is to
L D M' B l F l' B' M D' L'

what

F' R S' D F' M F D' S R' F
is to
??????????????????????????

In other words, 4-cycle corner/edge pairs again but this time every 
second corner comes from D instead of U. Any 4-cycle of these 
corner/edge pairs is ok. Find a short algorithm, don't use computer 
help. I have a hard time with it.

Cheers!
Stefan







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