We've done it this way too previously. But some people don't get it anyway.

/Gustav

GameOfDeath2 skrev:

>All this simulation isn't very much in the way of proof, is it?
>It's much quicker (and more formal and not empirical) to use 
>conditional probability to get the result.
>
>Initially, you select the correct door with probability 1/3.
>If you are correct, switching is guaranteed to fail, sticking is 
>guaranteed to win.
>If you are incorrect, switching is guaranteed to succeed, sticking is 
>guaranteed to fail.
>
>(Heuristically, in the less probable case switching fails and in the 
>more probable case switching succeeds. We can be more formal as 
>follows:)
>
>P(Win if switch)
>=P(Win if switch|first guess is correct)*P(first guess is correct)+P
>(Win if switch|first guess is incorrect)*P(first guess is incorrect)
>=0*1/3+1*2/3=2/3.
>
>P(Win if stick)
>=P(Win if stick|first guess is correct))*P(first guess is correct)+P
>(Win if stick|first guess is incorrect)*P(first guess is incorrect)
>=1*1/3+0*2/3=1/3.
>
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>Yahoo! Groups Links
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