Hi,
As far as I know, there are no proper way to obtain build directory in
conf.py.
But, as a adhoc way, you con obtain it through environment variables.
in Makefile:
BUILDDIR = _build
export BUILDDIR
in conf.py:
builddir = os.environ['BUILDDIR']
jinja_contexts = {
'messages': json.load(open(os.path.join(builddir,
"messages.json")))
}
Thanks,
Takeshi KOMIYA
2016年9月9日金曜日 17時55分22秒 UTC+9 Markus Schöpflin:
>
> I am using the Jinja extension from sphinxcontrib. For this I have added
> the
> following to conf.py:
>
> extensions = ['sphinxcontrib.jinja']
>
> import json
> jinja_contexts = {
> 'messages': json.load(open("messages.json"))
> }
>
> The file "messages.json" is created automatically during the build of the
> project, before sphinx-build is called. The file is located in the build
> directory of the project.
>
> Now I'm struggling to refer to that file from conf.py, as the current
> directory is set to the directory where conf.py is located (which is the
> source directory of the project) when conf.py is loaded.
>
> My workaround currently is to copy conf.py to the build directory and
> execute
> sphinx-build like so, with the current directory set to the build
> directory:
>
> sphinx-build -b html -c . -d doctree '/.../source' html
>
> Is there a way to avoid copying conf.py to the build directory first? E.g.
> any
> variable which holds the value of the directory where sphinx-build is
> executed
> in, which can be accessed from conf.py?
>
> I also tried to add -D build_dir='/...' to sphinx-build in the hope that
> maybe
> this would make build_dir defined when conf.py is evaluated, but this is
> not
> the case.
>
> TIA, Markus
>
>
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