Thank you, Allan, very informative and well put...

Jeff Garrison


On Thu, Jun 6, 2013 at 11:30 PM, AKS-Gmail-IMAP <[email protected]> wrote:

> No. The 15,000 psi is a maximum allowed stress. It is not yield stress
> psi. 30,000 psi yield stress would be for a minimum grade steel and is what
> you might use for steel yield stress for some unknown steel grade. You take
> that number and apply a factor to arrive at the maximum allowed stress that
> you are trying not to exceed. The factor number is proscribed by whatever
> steel design standard you are using and that number is different for the
> situation in question - as per that standard. The factor is not to be
> viewed as a factor of safety as you might be thinking. There are many
> things that come into play that you might not realize.  Load cycling is a
> big one for example.  As a general rule steel loaded to no more than 50% of
> its yield strength can be repeatedly loaded and unloaded for practically an
> infinite number of times before failing. That is why the 0.5 factor has
> been used for a long while and may be the origin for the 15,000 number when
> steel grades were typically bottoming out as 30,000 yield.
>
> The next time you are driving your car down the highway think about how
> many times you have stressed and unstressed in torsion the steel rod
> connecting the steering wheel to the steering gear box and whether or not
> someone used a yield or allowed stress number when sizing that bar.
>
> Allan Seidel
> St. Louis, MO
>
>
>
> On Jun 6, 2013, at 7:27 AM, Jeff Garrison <[email protected]>
> wrote:
>
> > Something else to remember / revise in your calculations is that the
> minimum
> >
> > Yield Strength of almost all steel pipe today is 30,000 psi, some going
> to
> > 33 or 35k.
> >
> > The 15,000 used in the "red book" (how long since it's been red?) is
> quite
> > out of date.
> >
> > Jeff Garrison
> > Project Manager
> > C 586-871-3705
> > Detroit Automatic Sprinkler Co.
> > 28501 Ryan Rd., Suite C
> > Warren, MI 48092
> > P 586-574-0100
> > F 586-574-0101
> > [email protected]
> >
> >
> >
> >
> > -----Original Message-----
> > From: [email protected]
> > [mailto:[email protected]] On Behalf Of
> Brad
> > Casterline
> > Sent: Wednesday, June 05, 2013 5:44 PM
> > To: [email protected]
> > Subject: RE: required section modulus (it don't get no easier)
> >
> > & Ken I wish your PL/4 would have occurred to me sooner (I was re-reading
> > your post last night). Since the trapeze member has two supports I see
> each
> > one handling half the force time half the distance, or, .5P x .5L, which
> is
> > equivalent to your PL/4. I would have simply asked you to give that some
> > thought...
> >
> >
> > -----Original Message-----
> > From: John Denhardt [mailto:[email protected]]
> > Sent: Wednesday, June 05, 2013 4:18 PM
> > To: [email protected]
> > Subject: RE: required section modulus (it don't get no easier)
> >
> > Rahe - I am so confused.  This is a requirement of the standard already.
> > Are you requiring that they comply with the standard?  That would be a
> great
> > starting point!
> >
> > John
> >
> > John August Denhardt, P.E., FSFPE
> > Strickland Fire Protection Incorporated
> > 5113 Berwyn Road
> > College Park, Maryland 20740
> > Office Telephone Number:  301-474-1136
> > Mobile Telephone Number:  301-343-1457
> > FIRE SPRINKLERS SAVE LIVES - Can you live without them?
> >
> >
> > -----Original Message-----
> > From: [email protected]
> > [mailto:[email protected]] On Behalf Of
> Rahe
> > Loftin - 7PCE
> > Sent: Wednesday, June 05, 2013 5:04 PM
> > To: SprinklerFORUM
> > Subject: Re: required section modulus (it don't get no easier)
> >
> > Ken,
> > You might mention that if one is trying to support a 6 inch pipe,
> requiring
> > 1/2 inch all thread rod with a trapeze using 3/8 inch all thread rod, as
> the
> > 6 inch pipe is moved from the middle of the span, one of the 3/8 ATRs
> will
> > begin to be supporting more of the 6 inch pipe load.  At some point, the
> 3/8
> > inch rod will no longer share the load properly leaving one of the rods
> > trying to support too much of the load.  Even if the section modulus is
> > correct, I always have the contractor use 1/2 inch ATR to support the
> > trapeze if they are trying to support 6 inch pipe.
> >
> > *
> > *
> > *Thanks*
> > *
> > *
> > *Rahe Loftin, PE *
> > *Fire Protection Engineer (AHJ)*
> > *General Services Administration*
> > *Region 7 - TX, OK, NM, AR, LA*
> > *Design & Construction 7PCE*
> > *
> > *
> > *c - 817-371-3102*
> > *o - 817-978-7299*
> >
> >
> > On Mon, Jun 3, 2013 at 9:59 AM, ParsleyConsulting <
> [email protected]
> >> wrote:
> >
> >> Whoops, forgot that to get to 1.09 for the required section modulus,
> >> you first have to divide PL by 4, then by 15,000.  See how easy it is
> >> for even a smart aleck like me to make a mistake? The answer was
> >> correct, but the explanation was flawed, that's why my teachers always
> >> asked to show the work.
> >>
> >>    65,696.4divided by 4= 16,421 and that divided by 15,000 = 1.094
> >>
> >> Forgetting a step like that got me much lower grades.
> >> *
> >>
> >> PARSLEY CONSULTING
> >>
> >> *
> >>
> >> Ken Wagoner
> >>
> >> 760.745.6181 voice
> >>
> >> 760.745.0537 fax
> >>
> >> website: www.ParsleyConsulting.com
> > <http://www.ParsleyConsulting.**com<http://www.ParsleyConsulting.com>
> >>>
> >>
> >> On 6/3/2013 7:51 AM, ParsleyConsulting wrote:
> >>
> >>> Brad,
> >>>    Part 1 - Gibberish.  Pure and simple.  The tables in NFPA 13
> >>> didn't reduce the "force" and "distance" by half in their
> >>> calculations.  It
> > simply
> >>> used the formula to calculate the maximum moment at the point of the
> >>> load for a simple beam, based on the maximum length of various pipe
> >>> sizes between hangers.  That's why the figures for 1" and 1-1/4" are
> >>> based on
> > 12'
> >>> between hangers.
> >>> The maximum moment is the "worst case", and was what the committee
> >>> saw as providing system designers with enough information to allow
> >>> them to not
> > use
> >>> trapeze members which would have excessive loads placed on them.
> >>>    The formula to determine maximum moment is PL/4, with P=weight of
> >>> pipe being supported in pounds (including 250#), and L=the length of
> >>> the span of the trapeze in inches. The moment is then divided by the
> >>> maximum allowable bending stress, which for steel is 15,000.
> >>>    The resulting equation looks like this:  (PL/4)/15,000 = required
> >>> section modulus. So, for 15' of 1-1/2" sch 40 pipe, the value of P
> >>> would equal 15' x 3.61 = 54.15 + 250 = 304.15#.  For an 18' span, the
> >>> value of
> > L
> >>> = 216".  Multiply PxL = 65,696.4, and then divide that value by
> >>> 15,000,
> > and
> >>> the result is a required section modulus for the worst case location
> >>> of
> > the
> >>> load (mid span) of 1.09 in³. That is just slightly less than doubling
> >>> the value for a 9'-0" span, however using that method would result in
> >>> a
> > larger
> >>> required section modulus, so it would work out in the end.
> >>>    The 4ab/a+b you reference is a method to calculate the equivalent
> >>> length of the trapeze, in order to reduce the value of "L" in the
> > original
> >>> equation. Going back to your 18' span, if the load were 3' from one
> >>> end, and 15' from the opposite end, that results in the equation
> >>> 4x180x36/180+36, which equals 120", or 10'.  The value of L in the
> >>> above equation is changed from 216"to 120", reducing the required
> >>> section modulus. PL/4 now becomes 304.15 x 120 = 36,498which is
> >>> divided by 4, resulting in 9,124.5, which is further divided by the
> >>> allowable bending stress of 15,000 for steel, with a final required
> >>> section modulus of
> > 0.6083
> >>> in³. Round that up to 0.61, and it matches the value in NFPA 13,
> >>> Table
> >>> 9.1.1.7.1(a) (2013).
> >>> No reduction by half anywhere in those equations.
> >>> Part 2 - Relatively correct regarding doubling the require section
> >>> modulus for a 9' span, however as the structural engineers in the
> >>> room
> > when
> >>> this table was expanded to include spans up to 16'-0" notedyou can
> >>> keep increasing the span to the point where the weight of the trapeze
> >>> itself
> > now
> >>> becomes an issue in the overall capacity to resist bending, and that
> >>> sort of calculation was one they were reluctant to provide without a
> > significant
> >>> amount of additional information.
> >>> Please note that this is my opinion only, and does not reflect that
> >>> of the NFPA 13 Hanging and Bracing Committee.
> >>> *
> >>>
> >>> PARSLEY CONSULTING
> >>>
> >>> *
> >>>
> >>> Ken Wagoner
> >>>
> >>> 760.745.6181 voice
> >>>
> >>> 760.745.0537 fax
> >>>
> >>> website: www.ParsleyConsulting.com
> > <http://www.ParsleyConsulting.**com<http://www.ParsleyConsulting.com>
> >>>>
> >>>
> >>> On 5/31/2013 7:36 PM, Brad Casterline wrote:
> >>>
> >>>> saw an e-mail the other day about 18 foot trapeze spans.
> >>>>
> >>>> wished someone had asked me.
> >>>>
> >>>> i would have said---either:
> >>>>
> >>>> section modulus is moment divided by stress. moment is half the
> > force(lb)
> >>>> times half the distance(in).
> >>>>
> >>>> the force is the weight of the water-filled pipe plus 250. the
> >>>> distance is 4ab/a+b.
> >>>>
> >>>> the stress is 15,000.
> >>>>
> >>>> or: double the required section modulus for a nine foot span.
> >>>>
> >>>>
> >>>> Brad Casterline, NICET IV
> >>>>
> >>>> Fire Protection Division
> >>>>
> >>>>
> >>>> FSC, Inc.
> >>>>
> >>>> P: 913-722-3473
> >>>>
> >>>> [email protected]
> >>>>
> >>>> www.fsc-inc.com
> >>>>
> >>>>
> >>>> Engineering Solutions for the Built Environment
> >>>>
> >>>>
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