So Ken, I'll ask you too,
What GPM do you come up with?
On Oct 1, 2016 2:28 PM, "Parsley Consulting" <[email protected]>
wrote:

> Travis,
>     that's the most worthwhile advice I've read on this forum in some
> time.  Just keep it as simple as possible.  The more complex one makes the
> math the greater the opportunity for a digit, a decimal, a square, a square
> root, take your pick, to applied incorrectly, and thus skew the results to
> where they're no longer relevant.
>
>     Look at equation 4.9.3 in -291.  It's exactly the same equation you
> quoted.  Very simple.
>
>      29.84 * c * d² * √p
>
>
>     Of course, I suppose the charts in -291 could be helpful if you didn't
> need the results calculated out to tenths of a gallon.  They're all the
> result of the same equation with a C = 1.00 so converting to a different
> hydrant outlet coefficient is relatively easy.
>
>     See disclaimer below.
> sincerely,
>
> *Ken Wagoner, SET Parsley Consulting*
>
>
>
>
>
>
>
>
> * 350 West 9th Avenue, Suite 206 Escondido, California 92025 Phone
> 760-745-6181 <760-745-6181> Visit our website
> <http://www.parsleyconsulting.com/> IMPORTANT NOTICE: This correspondence
> is not a Formal Interpretation issued pursuant to NFPA Regulations. Any
> opinion expressed is the personal opinion of the author and does not
> necessarily represent the official position of the NFPA or its Technical
> Committees. In addition, this correspondence is neither intended, nor
> should it be relied upon, to provide professional consultation or services
> It should be noted that the above is my opinion as a member of the NFPA
> Installation of Private Fire Service Mains and their Appurtenances
> Committee in accordance with the NFPA Regulations Governing Committee
> Projects and should therefore not be considered, nor relied upon, as the
> official position of the NFPA or its Committees *
>
>
> On 10/01/2016 11:51 AM, Travis Mack wrote:
>
> Follow the formula in the standards.
>
> 29.83 x hydrant coefficient x pumper modification x diameter x diameter x
> sqrt (pitot pressure)
>
> Keep it all simple. No need to overcomplicate everything.
>
> There are even several apps to put in your phone to do this stuff.
> Keep it all simple.
>
> Travis Mack, SET
> MFP Design, LLC
> "Follow" us on Facebook: https://www.facebook.com/pages/MFP-Design-
> LLC/92218417692
> Send large files to MFP Design via:
> https://www.hightail.com/u/MFPDesign
>
> Sent from my iPhone
>
> On Oct 1, 2016, at 11:35 AM, Brad Casterline <[email protected]>
> wrote:
>
> My pleasure Jeff, thanks for saying.
> On Oct 1, 2016 1:32 PM, "Jeff Normand" <[email protected]> wrote:
>
>> Thanks for sharing Brad.
>>
>> On Sat, Oct 1, 2016 at 1:28 PM, Brad Casterline <[email protected]>
>> wrote:
>>
>>> Say it's a 2.5" butt (small, smooth and well rounded my personal
>>> favorite) so C=.9.
>>>
>>> ((2.5/24) ^2) * PI = .034 ft^2.
>>> .034 * .9 = .0307 ft^2.
>>>
>>> Say pitot = 30 PSI.
>>> 30/.433=69.284 ft (h).
>>> v=(2gh)^.5=(2*32.2*69.284)^.5=69.8 ft/sec.
>>> .0307 ft^2 * 69.8 ft/sec = 2.05 ft^3/sec, * 7.48 * 60 = 920 GPM.
>>>
>>> That's not too shabby!
>>>
>>> Brad
>>>
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