On 12/19/2014 09:05 AM, Lei wrote:
Hi experts,
I want got a py-file named as try.py
The content is
--------------------------------
import sys
def cal(init_code):
try:
exec(init_code)
except:
print('OMG')
try:
if 'A0=' not in init_code:
print('OMG')
A0=A
print('A0=',A0)
except NameError as e:
print(e)
init_code = ''
for statement in sys.argv[1:]:
init_code += statement + '\n'
cal(init_code)
--------------------------------
When I run it via command line in Spyder, IPython console, (I am using
python 3.4)
I got error:
--------------------------------------------------------
In[1]: !python try.py A=10 p=5 n=730
OMG
name 'A' is not defined
--------------------------------------------------------
My idea is that the first try does not work porperly. Because in the
second try, the code "print('OMG')" works. But the code "A0=A" does not
work.
No I am pretty sure it is the first try that is throwing an exception
and that is why A is never defined. That is the issue with a naked
except, it will catch anything and you really don't know what failed. If
you want to find out what is happening do:
except as e:
print(e)
Note the 'as' this is way exceptions should be handled now. except, e is
deprecated. See here:
https://docs.python.org/2/tutorial/errors.html
The bigger question is what are you trying to do?
And why not do it in interest.py, which the above seems to be based on?
Lastly, I would really suggest going through the Python tutorial:
https://docs.python.org/3/tutorial/
Could you please help me with this?
Thanks in advance!
--
Adrian Klaver
[email protected]
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