Interesting idea...

Hey, Bradford, you can test that idea by doing a:

Print @SQL

Before the execute statement in the code I supplied earlier.  That might
show something...


-----Original Message-----
From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] 
Sent: Friday, September 05, 2003 13:35
To: SQL
Subject: RE: Concatenation assistance...

Because you pass the list in through a variable, the query actually 
expands to look like this to the server:
(x.cyb_record_num NOT IN ("'32','432','43','23','112'"))

In other words, you're looking for a record where cyb_record_num equals 
the whole string, not one value in a list of values.

Thanks,
Eric




"Bradford T Comer" <[EMAIL PROTECTED]>
09/05/2003 01:17 PM
Please respond to sql

 
        To:     SQL <[EMAIL PROTECTED]>
        cc: 
        Subject:        RE: Concatenation assistance...


I finally figured that out, thanks.

Here is a second question, I have a SP that I pass into it a list e.g.
'32','432','43','23','112' then I use that parameter for the WHERE
clause,
using IN e.g.
(CAST(x.cyb_record_num AS varchar(25)) NOT IN (@spExcludeListB))

However it still returns the records with ID's in the list. If i hard
code
it, works as it should:
(x.cyb_record_num NOT IN ('32','432','43','23','112'))

WTF???
Anybody have any pointers? I have been banging my head for an hour.

Brad



-----Original Message-----
From: Raster, Tim [mailto:[EMAIL PROTECTED]
Sent: Friday, September 05, 2003 9:31 AM
To: SQL
Subject: RE: Concatenation assistance...


Did you initialize your @NewRecordIDList = '' first?  If not, then it's
null, and null + varchar = null.


-----Original Message-----
From: Bradford T Comer [mailto:[EMAIL PROTECTED]
Sent: Friday, September 05, 2003 06:10
To: SQL
Subject: RE: Concatenation assistance...

Correction...it DOES display the @SID for the PRINT statement, however
after
the END I have this:

PRINT 'TEST'
PRINT 'HELLO' + LTRIM(@NewRecordIDList)

This displays the following:
TEST


That is it, why doesnt the @NewRecordIDList get displayed?

Brad

-----Original Message-----
From: Bradford T Comer [mailto:[EMAIL PROTECTED]
Sent: Friday, September 05, 2003 6:07 AM
To: SQL
Subject: Concatenation assistance...


Why doesn't this output anything? I know that the @SID has a AT least 1
value???
...
                 WHILE (@@FETCH_STATUS = 0)
                 BEGIN
                                 PRINT @SID

                                 -- appendIDTo @NewRecordIDList
                                 SET @NewRecordIDList = @NewRecordIDList
+ 
',' +
CAST(@SID AS VARCHAR(25))


                 END
...

Thanks
Brad
[EMAIL PROTECTED]






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