Actually, I'm still having a problem because the primary object is already a join and the next object that I append gets listed twice.
Example sel=select([a,b], from_obj=[a.outerjoin(b)]) sel.append( a.outerjoin(c,somecriteriaforthejoin)) str(sel) SELECT ,,, FROM a LEFT OUTER JOIN b ON .... , a LEFT OUTER JOIN c ON ... sel.execute() SQLError: (ProgrammingError) table name "a" specified more than once What I really need is: a.outerjoin(b).outerjoin(c) That is what I can't seem to find a way to dynamically generate. Thanks -Dennis On Mar 5, 3:16 pm, Michael Bayer <[EMAIL PROTECTED]> wrote: > there is append_from() > > joins know how to find their "components" that are already in the > selectable and replace them. > > On Mar 5, 2007, at 4:38 PM, Dennis wrote: > > > > > I'm playing around with dynamically building a query. I can append > > columns, where clauses, from objects etc... but what about the case > > where I want to modify the from obj with a join? > > > For example I can do this: > > > sel=select() > > sel.append_from(a) > > sel.append_from(b) > > sel.append_whereclause(a.c.id==b.c.id) > > > That won't work for an outerjoin though. I have a query that works > > like this now: > > > select ( [...], from_obj=[a.outerjoin(b)] ) > > > but I can't figure out a way to add the outerjoin dynamically. I > > looked at clause visitors but there doesn't seem like a way to > > actually modify an existing join. > > > Any thoughts? > > > Thanks > > Dennis --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to sqlalchemy@googlegroups.com To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
