On Jan 14, 2008, at 10:44 AM, Alexandre Conrad wrote:
> > model.Media.query.join(["catalog", > model > .CatalogChannel > .channel > ]).filter > (model.CatalogChannel.c.id_channel==c.playlist.id_channel).all() > like, are you sure you dont want to just say: model .Media .query .join (["catalog "]).filter (model.CatalogChannel.c.id_channel==c.playlist.id_channel).all() ? that is if you want the Media which contains a CatalogChannel with a certain id_channel. otherwise im still having trouble wrapping my head around what youre trying to do there. --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [EMAIL PROTECTED] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
