On Dec 18, 2008, at 3:04 PM, Andreas Jung wrote:
> On 10.12.2008 20:36 Uhr, Michael Bayer wrote:
>>
>> On Dec 10, 2008, at 2:27 PM, Andreas Jung wrote:
>>
>>> Hi there,
>>>
>>> is there some more efficient way for dictifying a resultset other
>>> than
>>>
>>> lst = list()
>>> for row in session.query(...).all():
>>>
>>> d = self.__dict__.copy()
>>> for k in d.keys():
>>> if k.startswith('_sa'):
>>> del d[k]
>>>
>>> lst.append(d)
>>>
>>> Especially the loop of the keys takes pretty long for large result
>>> sets
>>> and tables with lots of columns.
>>
>> the most efficient way would be to use a ResultProxy instead of the
>> ORM and to call dict() on each row. Otherwise a more succinct way
>> of what you're doing there, not necessarily much faster, might be
>>
>>
>> list = [
>> dict((k, v) for k, v in obj.__dict__.iteritems() if not
>> k.startswith('_sa'))
>> for obj in session.query.all()
>>
>
> Does SA contain some official API to introspect the list of defined
> synonyms for a particular class? The goal is to take values defined
> as a
> synonym also into account for the dictification (for backward
> compatiblity reasons for an existing codebase).
the mapper's get_property() method includes a "resolve_synonyms"
keyword arg that indicates a given key which points to a synonym
should return the actual referenced property, so a recipe that builds
upon this would look like:
set([mapper.get_property(p.key, resolve_synonyms=True) for p in
mapper.iterate_properties])
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