Kevin, the default behavior is for relations to be represented by
lists. If what you want is a tree structure where a directory can
only have a single parent, you would use backref=backref("parentdir",
uselist=False). Or at least that's how you'd do it in plain SA; i
haven't used the declarative base yet so I don't know if there's a
different syntax.
On Feb 1, 6:35 am, Kevin Dangoor <[email protected]> wrote:
> I've done many many-to-one relationships with SQLAlchemy, but there
> must be something obvious I'm doing wrong here:
>
> class Directory(Base):
> __tablename__ = "directories"
>
> id = Column(Integer, primary_key=True)
> name = Column(String, unique=True)
> subdirs = relation('Directory', backref="parentdir")
> parent_id = Column(Integer, ForeignKey('directories.id'))
>
> def __str__(self):
> return "Dir: %s" % (self.name)
>
> "Base" is standard declarative Base.
>
> The odd behavior that I'm seeing is that on a newly created Directory
> instance, both subdirs and parentdir are lists when I would expect
> parentdir to just be null or a Directory.
>
> This is using SQLAlchemy 0.5.2.
>
> I do hope there's something obvious that I missed...
>
> Thanks,
> Kevin
>
> --
> Kevin Dangoor
>
> email: [email protected]
> blog:http://www.BlueSkyOnMars.com
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