> -----Original Message-----
> From: sqlalchemy@googlegroups.com 
> [mailto:sqlalch...@googlegroups.com] On Behalf Of Hollister
> Sent: 20 June 2009 02:15
> To: sqlalchemy
> Subject: [sqlalchemy] Re: aggregation with count and 
> webhelpers.paginate
> 
> 
> Well, that worked great:
> 
>     q = meta.Session.query(m.Hit.referer, func.count(m.Hit.id))\
>         .group_by(m.Hit.referer)\
>         .order_by(func.count(m.Hit.id).desc())
> 
> Thanks!
> 
> ps: Is there a better way to specify the count in the order_by?
> 

If it's just that you don't like repeating yourself, you should be able
to save the result of func.count (untested):

     hit_count = func.count(m.Hit.id)
     q = (meta.Session.query(m.Hit.referer, hit_count)
          .group_by(m.Hit.referer)
          .order_by(hit_count.desc())


Simon

--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups 
"sqlalchemy" group.
To post to this group, send email to sqlalchemy@googlegroups.com
To unsubscribe from this group, send email to 
sqlalchemy+unsubscr...@googlegroups.com
For more options, visit this group at 
http://groups.google.com/group/sqlalchemy?hl=en
-~----------~----~----~----~------~----~------~--~---

Reply via email to