Actually, I finally figured this out with the help of the people on
IRC. Sorry for the noise.

On Jun 25, 1:21 pm, Mike <[email protected]> wrote:
> Hi,
>
> I'm sure this is a simple question, but my Google-fu has failed me. I
> need to convert the following into a sqlalchemy query and I just can't
> seem to get it right:
>
> SELECT
>  ACTHD.HOURTYPE,
>  sum(ACTHD.HOURS),
>  sum(ACTHD.AMT)
> FROM  myDatabase.dbo.TableOne ACTHD INNER JOIN
>       myDatabase.dbo.TableTwo HOURR ON ACTHD.HOURTYPE = HOURR.HOURTYPE
> where ACTHD.CHK_DOC_NO=13880
> GROUP by ACTHD.HOURTYPE
>
> I figured out the join part from the docs:
>
> qry = session.query(TableOne, TableTwo).filter(TableOne.HOURTYPE ==
> TableTwo.HOURTYPE)
>
> And I know you get the "sum" command from the "func" module, but how
> do I combine these?
>
> I am using SqlAlchemy 0.5.4p2, Python 2.5 on Windows XP against MS SQL
> Server 2000.
>
> Thanks!
>
> Mike
--~--~---------~--~----~------------~-------~--~----~
You received this message because you are subscribed to the Google Groups 
"sqlalchemy" group.
To post to this group, send email to [email protected]
To unsubscribe from this group, send email to 
[email protected]
For more options, visit this group at 
http://groups.google.com/group/sqlalchemy?hl=en
-~----------~----~----~----~------~----~------~--~---

Reply via email to