On Sep 19, 2009, at 11:41 AM, joeformd wrote:
> > When we tried that it made a sql query to get all the towns (towns are > loaded lazily) - that could be an awful lot of information, so this > would be a much faster query so, the most succinct (and efficient) query of all is session.scalar(exists().where(user_towns.c.user_id==current_user.id)) should return True/False right back > > On Sep 19, 4:33 pm, Michael Bayer <[email protected]> wrote: >> On Sep 19, 2009, at 10:19 AM, joeformd wrote: >> >> >> >>> Thanks for the speedy response Michael, >> >>> we came up with this: >> >>> current_user_has_town = bool(session.query(User).filter >>> (User.id==current_user.id).filter(User.towns.contains >>> (current_user)).count()) >> >>> which maybe has slightly clearer intent? >> >> if you already have the current_user, why not just say "town in >> current_user.towns" > > --~--~---------~--~----~------------~-------~--~----~ You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to [email protected] To unsubscribe from this group, send email to [email protected] For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en -~----------~----~----~----~------~----~------~--~---
