query() will return a tuple of the items listed in the query. In your query
you are asking for a and b objects, so that is what you get. If you want the
result to be individual columns directly, you need to list them
individually.

    db.query(a.a, a.acol1, b.b, b.bcol1).\
        select_from(orm.join(a, b, a.a== b.a)).all()

if there are duplicate names in a and b you need to apply .label() to
distinguish the columns.

Unless your select_from() is especially complicated this can be simplified
and eliminate the subselect in the generated code

     db.query(a.a, a.acol1, b.b, b.bcol1).join((b, a.a== b.a)).all()


or if you have foreign keys defined between a and b

    db.query(a.a, a.acol1, b.b, b.bcol1).join(b).all()

--

You received this message because you are subscribed to the Google Groups 
"sqlalchemy" group.
To post to this group, send email to sqlalch...@googlegroups.com.
To unsubscribe from this group, send email to 
sqlalchemy+unsubscr...@googlegroups.com.
For more options, visit this group at 
http://groups.google.com/group/sqlalchemy?hl=.


Reply via email to