Michael Bayer <[email protected]> writes: > if the issue is that you have a query(), and you like to say > somequery.filter(q == "x"), you'd turn query() into a "subquery" > (i.e. an alisaed SQLAlchemy expression object) using q.subquery(), > and then into a "scalar" subquery using as_scalar(), which means the > select() construct now behaves like a column. as_scalar() is also > available directly on a select() construct.
That's it - thanks! I see some attempts in my log to try to use as_scalar(), but only directly on the query object which doesn't support that method. I didn't think to put it together with subquery() first, though in hindsight that makes perfect sense. Thanks again. -- David -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/sqlalchemy?hl=en.
