thx, is there a way to set that up, or something similar?

after giving it thought, maybe polymorphic_on isn't what i need.  in some
sense, table "A" is similar to a generic container, and i want to constrain
the type of "C" depending on "A"'s type column.  is there a way to do this?

On Wed, May 5, 2010 at 5:15 PM, Michael Bayer <[email protected]>wrote:

>
> On May 5, 2010, at 5:01 PM, Timmy Chan wrote:
>
> i have 4 tables, a, b, c, d.
>
> a has one-to-many relation with b, b with one-to-one relationship with c, c
> is a polymorphic on a.type, with d being one of the polymorphic types.
>
> is there a way to implement this?
>
> details:
>
> this is what im trying to do in sqlalchemy:
>
>     a = Table('a', metadata,
>               Column( 'id', Integer(), primary_key=True ),
>               Column( 'type', UnicodeText() ) )
>
>     b = Table('b', metadata,
>               Column( 'id', Integer(), primary_key=True ),
>               Column( 'a_id', Integer(), ForeignKey('a.id') ) )
>
>     c = Table('c', metadata,
>               Column( 'id', Integer(), primary_key=True ),
>               Column( 'b_id', Integer(), ForeignKey('b.id') ),
>               Column( 'class_id', Integer() ) )
>
>     d = Table('d', metadata,
>               Column( 'id', Integer(), primary_key=True ),
>               Column( 'data', Integer() )
>
> mappers
>
>     mapper( A, a )
>     mapper( B, b, properties={'a': relationship( A,
> uselist=False,backref='b',
>            'c':relationship( C, uselist=False, backref='b') })
>
>     # Does a full join, does not work
>     mapper( C, c, polymorphic_on = a.c.type )
>     mapper( D, d, inherits=C, polymorphic_identity = "D" )
>
>
> how can i change c to polymorphic on a, through the relationship?   is
> there a way to sort by d.data?  (b-c/d is one-on-one).
>
>
> this mapping is incorrect.     mapper(C) cannot be polymorphic on a table
> which is not part of its mapping, and mapper(C) does not contain an
> "inherits" keyword to that of A.   Usually the "polymorphic_on" setting is
> on the base-most mapper in the hierarchy and its not clear here which mapper
> you intend for that to be.
>
>
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