Nevermind. This seems to work:
subq =
session.query(func.count('*').label('countall')).select_from(ReportableCondition).subquery()
qry = session.query(ReportableCondition.disease,
func.count(1).label('number'),
(cast(100*func.count(1), Float) /
subq)).group_by(ReportableCondition.disease)
On Aug 31, 5:42 pm, nospam <[email protected]> wrote:
> I get an error saying the countall doesn't appear in the groupby, or
> its not an aggregating function.
>
> sqlalchemy.exc.ProgrammingError: (ProgrammingError) column
> "anon_2.countall" must appear in the GROUP BY clause or be used in an
> aggregate function
>
> session = SqlMapping().createSession()
>
> subq =
> session.query(func.count('*').label('countall')).select_from(ReportableCondition).subquery()
>
> qry = session.query(ReportableCondition.disease,
> func.count(1).label('number'),
> ((100*func.count(1)) /
> subq.c.countall)).group_by(ReportableCondition.disease)
>
> for result in qry:
> print result
>
> On Aug 29, 5:04 pm, Mike Conley <[email protected]> wrote:
>
>
>
> > This should work
>
> > subq = sess.query(func.count('*').label('countall')).\
> > select_from(FilmParticipation).subquery()
>
> > qry = sess.query(FilmParticipation.PartType,
> > func.count(1).label('Amount'),
> > ((100*func.count(1)) / subq.c.countall)).\
> > group_by(FilmParticipation.PartType)
>
> > --
> > Mike Conley
>
> > On Mon, Aug 29, 2011 at 3:05 PM, nospam <[email protected]> wrote:
> > > I'm trying to construct a query in sqlalchemy similiar to this:
> > > SELECT FilmParticipation.PartType, COUNT(*) AS Amount,
> > > 100*COUNT(*) /(SELECT count(*) FROM FilmParticipation) AS
> > > Percentage_of_Total
> > > FROM FilmParticipation
> > > GROUP BY FilmParticipation.PartType;
>
> > > I create a subquery for the nested select, but, I get a
> > > NoSuchColmnError on the percentage part.
>
> > > Any ideas how this could be constructed?
>
> > > Cheers,
> > > Lars
>
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