order_by('counted')
?
there's a feature for 1.0 that will actually search out "counted" when you pass
as a string and match it up too.
On Jul 30, 2014, at 3:35 PM, Jonathan Vanasco <[email protected]> wrote:
> Revisiting this question, with coalesce. The target sql is:
>
> SELECT
> letter
> ,COALESCE(cache_counted, 0) AS counted
> FROM letters
> ORDER BY counted DESC
>
> The closest I can get to it is this:
>
> dbSession.query(
> sqlalchemy.func.count( model.Letters.letter ),
> sqlalchemy.func.coalesce( model.Letters.cache_counted,
> 0).label('counted'),
> ).order_by(
> sqlalchemy.func.coalesce( model.Letters.cache_counted, 0).desc
> )
>
>
>
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