On Fri Jan 30 2015 at 4:42:42 PM Jonathan Vanasco <[email protected]>
wrote:
>
> This should generate your second query:
>
>
> q = s.query(Foo)\
> .join(
> Boo,
> Foo.id == Boo.id
> )\
> .join(
> Bar,
> Boo.id == Bar.id
> )\
> .first()
>
>
But I already have relationships set up so I'd like to not have to manually
write out these joins, but also have the relevant columns loaded into my
relationship:
q = s.query(Foo).options(joinedload(Foo.boo))
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