For the record, this should have a '==' for the join condition: q = intersect.join(query_select, query_select.c.sid == intersect.c.sid)
On Wednesday, July 8, 2015 at 7:48:54 PM UTC-5, Horcle wrote: > > Weird, I had tried using the subquery() method earlier, but it didn't > work. Not sure why, but now it is returning the desired query object. (I > guess stepping away from this for a few hours was a good idea, eh?!) > > Thanks! > > Greg-- > > On Wednesday, July 8, 2015 at 6:24:16 PM UTC-5, Jonathan Vanasco wrote: >> >> you probably need to modify the various objections with a `.select()` or >> `.subquery()` >> >> e.g: >> query_select = query.select() >> q = intersect.join(query_select, query_select.c.sid, intersect.c.sid) >> >> pay attention to the docs on what the various methods return. some >> return a selectable, others don't. you can usually toggle around the >> different forms with .select, .subquery, .alias (and there are a few others) >> >> -- You received this message because you are subscribed to the Google Groups "sqlalchemy" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected]. Visit this group at http://groups.google.com/group/sqlalchemy. For more options, visit https://groups.google.com/d/optout.
