Just do it in Python:
res = []
for hpoint in session.query(HistoryPoint).all():
res.setdefault(hpoint.vehicle_id, []).append({'id':hpoint.id,'location':
str(hpoint.location)})
On Tuesday, September 22, 2015 at 6:48:14 PM UTC+3, Johnny W. Santos wrote:
>
> Supose I have the models below, how could I query for a result like this:
>
> [
> {1: [{"id": 3, "location": "POINT(23.23423423 54.234524234)"},{"id": 4,
> "location": "POINT(23.23423423 54.234524234)"}]},
> {2: [{"id": 45, "location": "POINT(78.23423423 43.234524234)"},{"id": 67
> , "location": "POINT(34.2347683423 74.234524234)"}]},
> ]
>
> The keys being the vehicle id and a list of HistoryPoints values.
>
> Supposing I have more fields in HistoryPoint and is prefered to query on
> it due some filter conditions.
>
>
> class Vehicle(Base):
> id = Column(Integer, primary_key=True)
> identifier = Column(Integer)
>
>
> class HistoryPoint(Base):
> vehicle_id = Column(Integer, FokeignKey('vehicles.id'))
> location = Column(Geography('POINT'))
>
> vehicle = relationship('Vehicle', backref='history')
>
>
> I'm really having a hard time on this, any help will be appreciated
>
> Johnny
>
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