On Mon, Mar 21, 2016 at 5:21 PM, <c.bu...@posteo.jp> wrote:
> Hi Michal
>
> > q.join(ReferenceAuthor, ReferenceAuthor.c.Index == 0)
>
> Ah, of course! Thank you very much!
>
> But... ;)
>
> This Python code
>
> return self.session.query(Reference) \
> .filter_by(_mark = False) \
> .join(Periodical) \
> .join(ReferenceAuthor,
> ReferenceAuthor.c.Index==0) \
> .join(Person) \
> .order_by(Periodical._name) \
> .order_by(Person._lastname) \
> .all()
>
>
>
> The SQL echoed looks ok:
>
> SELECT "Reference"."ID" AS "Reference_ID",
> "Reference"."HasLabel" AS "Reference_HasLabel",
> "Reference"."PeriodicalID" AS "Reference_PeriodicalID"
> FROM "Reference"
> JOIN "Periodical"
> ON "Periodical"."ID" = "Reference"."PeriodicalID"
> JOIN "ReferenceAuthor"
> ON "ReferenceAuthor"."Index" = ?
> JOIN "Person"
> ON "Person"."ID" = "ReferenceAuthor"."PersonID"
> WHERE "Reference"."HasLabel" = 0
> ORDER BY "Periodical"."Name",
> "Person"."LastName"
>
> But result doesn't looks like that it is secondary sorted by first
> persons lastname. See as an example one "Periodical._name" (Bmc
> Geriatrics) and the first persons lastname of 8 References.
>
> Bmc Geriatrics
> Dapp
> Tuntland
> Hsu
> van der Elst
> Khatib
> Hermans
> van Buul
> Lichtner
>
You are missing the join condition between ReferenceAuthor and Reference.
You probably want something like this:
join(ReferenceAuthor,
and_(ReferenceAuthor.c.ReferenceId == Reference.ID),
ReferenceAuthor.c.Index == 0))
Simon
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