Actually I think in this case you could probably leave the "secondary"
argument as the association table itself, but change the join
condition via the "primaryjoin" parameter. Something like this
(completely untested):
class User(Base):
id = Column(Integer, primary_key=True)
managed_teams = relationship(
'Team',
secondary=user_team_association_table,
primaryjoin=sa.and_(user_team_association_table.c.user_id == id,
user_team_association_table.c.is_manager==sa.true()),
)
Simon
On Thu, Jun 15, 2017 at 12:26 PM, <[email protected]> wrote:
> Thanks Simon. While this seems to have worked, I only run into the next
> error. Mind you, I’m somewhat new to Alchemy and my SQL is rather rusty at
> the moment. My current approach
>
> managed_teams = relationship("Team",
> secondary="join(user_team_association,
> user_team_association.c.is_manager==true)",
> backref="managers")
>
> seems to be an incomplete join. I’ll look into this tomorrow…
> Jens
>
>
> On Thursday, June 15, 2017 at 6:25:00 PM UTC+10, Simon King wrote:
>>
>> Table objects put columns under the ".c" attribute, so you probably
>> need "user_team_association.c.is_manager".
>>
>> Simon
>>
> --
> SQLAlchemy -
> The Python SQL Toolkit and Object Relational Mapper
>
> http://www.sqlalchemy.org/
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SQLAlchemy -
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http://www.sqlalchemy.org/
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