Ok, that works almost fine:
>>> func.jsonb_agg(literal_column(models.OrderUINTable.name + '.*'))
'jsonb_agg(OrderUIN.*)'
The problem is OrderUIN. It must be quoted: jsonb_agg("OrderUIN".*)

чт, 6 сент. 2018 г. в 17:44, Антонио Антуан <a.ch....@gmail.com>:

> Another one fail:
> func.jsonb_agg(*models.OrderUINTable.c.values()) - PG error: "function
> jsonb_agg(integer, text, numeric, text, text, text, text) does not exist"
>
>
> четверг, 6 сентября 2018 г., 17:28:37 UTC+3 пользователь Антонио Антуан
> написал:
>
>> Hi guys.
>> I'm using sqlalchemy 1.1.13, want to construct that query:
>> select o.*, jsonb_agg(ou.*) from "Orders" o left join "OrderUIN" ou on
>> ou."OrderID" = o."OrderID" group by o."OrderID"
>>
>> I tried that options:
>> - func.jsonb_agg(OrderUINTable), got select o.*, jsonb_agg() from
>> "Orders"... Empty argument for the function, as you can see.
>> - func.jsonb_agg(OrderUINTable.columns.values()), got can't adapt type
>> 'Column'
>> - func.jsonb_agg(OrderUINTable.alias), got TypeError: self_group() got an
>> unexpected keyword argument 'against'
>>
>> How can I implement it?
>>
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Антон

-- 
SQLAlchemy - 
The Python SQL Toolkit and Object Relational Mapper

http://www.sqlalchemy.org/

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