Kevin O'Gorman wrote: > If I go on to the second table, it appears to finish normally, but when I > try to look at the database with sqlite3, a command-line tool for > interacting with SQLite, it says the database is corrupt.
What version? > If however, I split the program into two programs, one for each table, and > run them one after another, all is well. Same code, each with parts of it > if-else-ed out. It's possible that there is a bug in your code. Which you have not shown. Regards, Clemens _______________________________________________ sqlite-users mailing list sqlite-users@mailinglists.sqlite.org http://mailinglists.sqlite.org/cgi-bin/mailman/listinfo/sqlite-users
